Q:

Tabitha is trying to find the equation of a line perpendicular to y = 1 over 2 x βˆ’ 5 in slope-intercept form that passes through the point (2, βˆ’7). Which of the following equations will she use?

Accepted Solution

A:
Answer:[tex]y=-2x-3[/tex]Step-by-step explanation:we know thatIf two lines are perpendicularthenthe product of their slopes is equal to minus oneso[tex]m1*m2=-1[/tex]Step 1Find the slope of the given line we have[tex]y=\frac{1}{2}x-5[/tex]the slope of the given line is equal to[tex]m1=\frac{1}{2}[/tex]Step 2Find the slope of the line perpendicular to the given line[tex]\frac{1}{2}*m2=-1[/tex][tex]m2=-2[/tex]Step 3Find the equation of the line into slope intercept form[tex]y=mx+b[/tex]we have[tex]m=-2[/tex][tex]point(2,-7)[/tex]substitute and solve for b[tex]-7=-2*(2)+b[/tex][tex]-7=-4+b[/tex][tex]b=-7+4=-3[/tex]The equation of the line is equal to[tex]y=-2x-3[/tex]